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in Arithmetic Progression by (50.9k points)
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Which term of the AP 64, 60, 56, 52, 48, …. is 0?

1 Answer

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Best answer

To Find: we need to find n when an = 0

Given: The series is 64, 60, 56, 52, 48, … and an = 0

a1 = 64, a2 = 60 and d = 60 – 64 = –4

(Where a = a1 is first term, a2 is second term, an is nth term and d is common difference of given AP)

Formula Used: an = a + (n - 1)d

an = 0 = a1 + (n –1)(– 4)

0 – 64 = (n –1)(– 4) [subtract 64 on both sides]

– 64 = (n –1)(– 4)

64 = (n –1)4 [Divide both side by '–']

16 = (n –1) [Divide both side by 4]

n = 17th [add 1 on both sides]

The 17th term of this AP is equal to 0.

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