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Find the sum of all natural numbers from 1 and 100 which are divisible by 4 or 5.

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To Find: The sum of all natural numbers from 1 to 100 which are divisible by 4 or 5.

A number divisible by both 4 and 5 should be divisible by 20 which is the LCM of 4 and 5.

Sum of numbers divisible by 4 OR 5 = Sum of numbers divisible by 4 + Sum of numbers divisible by 5 - Sum of numbers divisible by both 4 and 5.

Sum of numbers divisible by 4 = 4+8+12+....100

= 4(1+2+3+.....25) = 4 x 25/2[2+24] = 50 x 26 = 1800

Sum of numbers divisible by 5 = 5 +10+15+20+......100 = 5(1+2+3+.....20)

= 5 x 20/2[2+19] = 50 x 21 = 1050

Sum of numbers divisible by 20 = 20+40+60+.... 100

= 20(1+2+3+4+5) = 20 x 15 = 300

Required sum = 1800+1050 - 300 = 2550

Sum of numbers which are divisible by 4 or 5 is 2550

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