Given :
Two cars start together from the same place and move in the same direction.
The first car moves with a uniform speed of 60km/hr.
The second car moves with 48km/hr in the first hour and increases the speed by 1 km each succeeding hour.
Let the cars meet at n hours.
Distance travelled the first car in n hours = 60×n
Distance travelled by the second car in n hours is
= n/2{2x48+(n-1)x1}
Tip: -
When the cars meet the distances travelled by cars are equal.
n/2{2x48+(n-1)x1} = 60 x n
96 + (n - 1) = 120
n = 25
∴ The two cars meet after 25 hours from their start and overtake the first car.