Question

A man accepts a position with an initial salary of ₹26000 per month. It is understood that he will receive an automatic increase of ₹250 in the very next month and each month thereafter.

Find this (i) salary for the 10^th month, (ii) total earnings during the first year.

Answer 1

Given: -

An initial salary that will be given = ₹26000

There will be an automatic increase of ₹250 per month from the very next month and thereafter.

Hint: - In the given information the salaries he receives are in A.P.

Let the number of the month is n.

Initial salary = a = ₹26000

Increase in salary = common difference = d = ₹250

i. Salary for the 10^th month,

n = 10,

Salary = a + (n - 1)×d

= 26000 + (10 - 1)×250

= 28250

∴ Salary for the 10th month = ₹28250

ii. Total earnings during the first year = sum off all salaries received per month.

Total earnings = n/2[2 x a+(n-1) x d]

Here n = 12.

Total earnings = 12/2[2 x 26000+(12-1) x 250]

= 6×(42000 + 2750)

= 268500

Total earnings during the first year = ₹268500