Given: -
Total debt = Rs.36000
A man pays this debt in 40 annual instalments that forms an A.P.
After annual instalments, that man dies leaving one - third of the debt unpaid.
So,
Within 30 instalments he pays two - thirds of his debt.
Sum of n terms in an Arithmetic Progression = n/2[2 x a+(n-1) x d]
He has to pay 36000 in 40 annual instalments,
36000 = 40/2[2 x a+(40 -1) x d] → (1)
Where,
a = amount paid in the first instalment,
d = difference between two Consecutive instalments.
He paid two – a third of the debt in 30 instalments,
2/3(36000) = 30/2[2 x a+(30 -1) x d] → (2)
From equations (1) & (2) we get,
a = 510 & d = 20
∴The value of the first instalment is Rs.510.