Question

A body of mass 0.5 kg travels in a straight line with velocity v = a x^3/2 where a = 5 m^-(1/2) s^-1 . What is the work done by the net force during its displacement from x = 0 to x = 2 m? 

Answer 1

Mass of the body, m = 0.5 kg

Velocity of the body is governed by the equation,  v = a x^3/2 with a = 5 m^-1/2 s^-1 

Initial velocity, u (at x = 0) = 0

Final velocity v (at x = 2 m) = 10√2 m/s

Work done, W = Change in kinetic energy