Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
107 views
in Arithmetic Progression by (71.7k points)
closed by
Determine k, so that `K^(2)+4k+8, 2k^(2)+3k+6` and `3k^(2)+4k+4` are three consecutive terms of an AP.

1 Answer

0 votes
by (71.6k points)
selected by
 
Best answer
Since, `k^(2)+4k+8, 2k^(2)+3k+6` and `3k^(2) +4k+4` are consecutive terms of an AP.
` :. 2k^(2)+3k+6-(k^(2)+4k+8)=3k^(2)+4k+4-(2k^(2)+3k+6)=` Common difference
`implies 2k^(2)+3k+6-k^(2)-4k-8=3k^(2)+4k+4-2k^(2)-3k-6`
` implies " " k^(2)-k-2=k^(2)+k-2`
`implies " " -k=kimplies2k=0impliesk=0`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...