Correct Answer - A::B::C::D
Here, there are 2 red balloons `R_(1),R_(2),`
3 blue balloons `B_(1),B_(2),B_(3).`
4 green balloons `G_(1),G_(2),G_(3),G_(4).`
`therefore"the sample space"`
`S={R_(1),R_(2),B_(1),B_(2),B_(3),G_(1),G_(2),G_(3),G_(4)}" "thereforen(S)=9`
(1) Let A be the event that pranali gets a red balloon.
`ThenA={R_(1),R_(2)}" "thereforen(A)=2`
`P(A)=(n(A))/(n(S))=(2)/(9)`
`therefore"the probability that pranali gets a red balloon is" (2)/(9).`
(2) Let B be the event that pranali gets a blue balloon.
`ThenB={B_(1),B_(2),B_(3)}" "thereforen(B)=3`
`P(B)=(n(B))/(n(S))=(3)/(9)=(1)/(3)`
`therefore "the probability that pranali gets a blue balloon is" (1)/(3).`
Let C be the event that pranali gets a green balloon.
`Then C={G_(1),G_(2),G_(3),G_(4)}" "thereforen(C)=4`
`P(C)=(n(C))/(n(S))=(4)/(9)`
`therefore"the probability that pranali gets a green balloon is"(4)/(9).`