(i) Both the customers visit the shop on the same day, i.e., there. are 6 days (Monday to Saturday) and each is equally likely.
`therefore` Probability of both will visit on the same day
= First will go on Monday and the other will also go on Monday or first will go on Tuesday and other will go on Tuesday
:
or first will go on Saturday and other will also go on Saturday
`=(1)/(6)xx(1)/(6)+(1)/(6)xx(1)/(6)+...+(1)/(6)xx(1)/(6)=6xx(1)/(6)xx(1)/(6)=(1)/(6)`
Alternative Method:
First person will definitely go to the market on any of the six days with probability 1 (sure event). If both go to the market same day then second person has only 1 choice (only that 1 day when first goes). So, its probability of going to the market `=(1)/(6).`
`therefore" Required probability "=1xx(1)/(6)=(1)/(6)`
(ii) First person will definitely go to the market on any of the six days with probability 1 (sure event). Since, both will not go on the same day, so second person has now only 5 choices (except this 1 day when first go to the market). So, the probability of second
man go to the other day `=(5)/(6).`
`therefore" Required probability "=1xx(5)/(6)=(5)/(6)`
(iii) There are 5 consecutive days, i.e., Monday Tuesday, Tuesday Wednesday, Wednesday Thursday, Thursday Friday, Friday Saturday.
`therefore" Required probability "=5xx(1)/(6)xx(1)/(6)=(5)/(36)`
