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A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope. Find(i) the area of that part of the field in which the horse can graze.(ii) the increase in the grazing area if the rope were 10 m long instead of 5 m.

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Area= area of sector with `(theta=90^0)=theta/360^0*pi*r^2`
=90/360*22/7*25
=19.625 `m^2`
Increase in area=`theta/360*pi(10m)^2-19.625`
=`90/360*3.14*100-19.625`
=58.875 `m^2`

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