Question

Calculate the area of the designed region in Fig. 12.34 common between the two quadrants of circles of radius 8 cm each.

Answer 1

as we can see that
ar(2 quad) = area (square) + ar(design)
ar(design) = 2* ar(quadrant) - ar(square)
`= 2*1/4* pi r^2 - r^2`
`= (pi r^2)/2 - r^2`
`= r^2(pi/2 - 1)`
`=8^2(1/2*22/7 - 1)`
`= 64(11-7)/7`
`= 256/7 cm^2`
answer