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In Fig. 2, `Delta AHK` is similar to `Delta ABC`. If AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find AC.

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`Delta AHK~ Delta ABC`
`rArr (AK)/(AC)=(HK)/(BC)rArr (10)/(BC) =(7)/(3.5),` where AC= x cm
`rArr x= (10xx3.5)/(7)=5`
`:. AC= 5cm`

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