Question

PQ and RS are two parallel chords of a circle whose centre is O and radius is 10 cm. If PQ =16cm and RS=12cm, find the distance between PQ and RS, If they lie on the same side of the Centre O.

Answer 1

by the use of pythagoras theorem
`OM^2 = OP^2 - PM^2 = (10)^2 - (8)^2 = 100 - 69 = 36`
`OM= 6`cm
`ON^2 = OR^2 - RN^2 = (10)^2 - (6)^2 = 100-31= 64`
`ON= 8`cm
`MN=ON-OM= 8-6= 2`cm
`MN=2 `cm