Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
105 views
in Linear Equations by (71.6k points)
closed by
Two straight paths are represented by the equations ` x - 3y = 2` and `-2x + 6y = 5`. Check whether the paths cross each other or not.

1 Answer

0 votes
by (71.7k points)
selected by
 
Best answer
Given linear equations are
`x-3y-2=0 " " ...(i)`
and `-2x+6y-5=0" " ...(ii)`
On comparing both the equations with `ax+by+c=0`, we get
`a_(1)=1,b_(1)=-3`
and `c_(1)=-2" " `[from Eq.(i)]
`a_(2)=-2,b_(2)=6`
and `c_(2)=-5" " `[from Eq.(ii)]
Here, `" " (a_(1))/(a_(2))=(1)/(-2)`
`(b_(1))/(b_(2))=(-3)/(6)=-(1)/(2)` and `(c_(1))/(c_(2))=(-2)/(-5)=(2)/(5)`
i.e., `" " (a_(1))/(a_(2))=(b_(1))/(b_(2))!=(c_(1))/(c_(2))" "` [parallel lines]
Hence, two straight paths represented by the given equation never cross each other, because they are parallel to each other.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...