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in Determinants by (15.3k points)
edited by

Mark the tick against the correct answer in the following:

\(\begin{vmatrix} sin \alpha & cos \alpha & sin(\alpha + \delta) \\[0.3em] sin \beta & cos \beta & sin(\beta + \delta) \\[0.3em] sin \gamma &cos \gamma & sin(\gamma + \delta) \end{vmatrix}\) = ?

|(sinα, cosα, sin(α + δ)),(sinβ, cosβ, sin(β + δ))(sin γ, cosγ, sin(α + δ)) = ?

A. 0 

B. 1 

C. sin (α + δ) + sin (β + δ)+ sin (γ + δ) 

D. none of these

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1 Answer

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by (15.9k points)
edited by

Correct answer A. 0

To find: value of \(\begin{vmatrix} sin \alpha & cos \alpha & sin(\alpha + \delta) \\[0.3em] sin \beta & cos \beta & sin(\beta + \delta) \\[0.3em] sin \gamma &cos \gamma & sin(\gamma + \delta) \end{vmatrix}\)

Formula Used: sin(A+B) = sinAcosB+cosAsinB

We have, \(\begin{vmatrix} sin \alpha & cos \alpha & sin(\alpha + \delta) \\[0.3em] sin \beta & cos \beta & sin(\beta + \delta) \\[0.3em] sin \gamma &cos \gamma & sin(\gamma + \delta) \end{vmatrix}\)

Applying C1 → cos (δ) C1

= 0 

When two columns are identical then the value of determinant is 0

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