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The escape velocity of a projectile on the earth’s surface is 11.2 kms−1 . A body is projected with thrice this speed from the earth’s surface, then the speed of body far away from the earth is

(a) 22.4/√2 km s-1

(b) 31.68 kms-1

(c) 22.4 kms-1

(d) 31.68 kms-1

1 Answer

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Best answer

Correct option is (b) 31.68 kms−1

Escape velocity, Ve = 11.2 kms-1

Velocity of projection, V = 3Ve

By the law of conservation of energy,

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