For semicircle with diameters PS,
Radius = 6 cm
`:.` Area of such semicircle `= (1)/(2) pi r^(2) = (1)/(2) xx (22)/(7) xx 6^(2) = (396)/(7) cm^(2)`
Diameter `PS = 6 + 6 = 12 cm`
`:. PQ = QR = RS = 4 cm`
For semicircle with diameter QS, radius = 4 cm
`:.` Its area `= (1)/(2) pi r^(2) = (1)/(2) xx (22)/(7) xx 4^(2) = (176)/(7) cm^(2)`
For semicircle with diameter PQ, radius = 2 cm
`:.` Its area `= (1)/(2) xx (22)/(7) xx 2^(2) = (44)/(7) cm^(2)`
`:.` Area of shaded region `= (396)/(7) - (176)/(7) + (44)/(7) = (264)/(7) = 37.71 cm^(2)`
Given: PS = diameter of circle
and radius (r) = 6 cm
diameter `PS = 2 xx r`
`rArr PS = 2 xx 6 " " PS = 12 cm`
`PQ = QR = RS = (12)/(3) = 4 cm` each.
Hence, required perimeters = circumference of semicircle with radius 6 cm + circumference of semicircle with radius 4 cm + circumference of semicircle with radius 2 cm.
`6 pi + 4 pi + 2pi = 12 pi cm`