Question

For the following distribution

the sum of lower limits of the median class and modal class is
A. 15
B. 25
C. 30
D. 35

Answer 1

Correct Answer - B
Here,

Now, `(N)/(2)=(66)/(2)=33`, Which lies in the interval 10-15. Therefore, lower limit of the mediuan class is 10. The highest frequency is 20, which lies in the interval 15-20. Therefore lower limit modal class is 15. Hence, required sum is 10+15=25.