Total number of bulbs, n(S)=24
Let `E_(1)`=Event of selecting not defective bulb=Event of selecting good bulbs
`n(E_(1))=18`
`therefore P(E_(1))=(n(E_(1)))/(n(S))=(18)/(24)=(3)/(4)`
Supposem the selected bulb is defective and not replaced then the total number of bulbs remains in a cartoon, n(S)=23.
In them, 18 are good bulbs and 5 are defective bulbs.
`therefore` P(selecting second defective bulb)=`(5)/(23)`