Given, a die has its six faces marked {0,1,1,1,6,6}
`therefore` Total sample space, n(S)=`(6)^(2)=36`
(i) The different score which are possible are 6 scores i.e. 0,1,2,6,7 and 12.
(ii) Let E=Event of getting a sum 7
={(1,6),(1,6),(1,6),(1,6),(1,6),(1,6),(6,1),(6,1),(6,1),(6,1),(6,1),(6,1)}
`therefore n(E)=12`
`therefore P(E)=(n(E))/(n(S))=(12)/(36)=(1)/(3)`