Given that , A bag contains total number of balls=24
A bag contains number of red balls=x
A bag contains number of white balls=2x
and a bag contains number of blue balls=3x
By contains, x+2x+3x=24
`Rightarrow 6x=24`
`therefore x=4`
`thererfore` Number of red balls=x=4
Number of white balls=`2x=2xx4=8`
and number of blue balls=`3x=3xx4=12`
So, total numbe of outcomes for a red balls is selected at random in a bag contain 24 balls,
`Rightarrow n(S)=24`
(i) Let `E_(1)`=Event of selecting a ball is selected at random in a bag contains 24 balls.
`therefore n(E_(1))`=Number of white balls+Number of blue balls
`therefore` `"Required probability"=(n(E_(1)))/(n(S))=(20)/(24)=(5)/(6)`
(ii) Let `E_(2)`=Event of selecting a ball which is white
`therefore n(E_(2))`=Number of white balls=8
So, required probability= `(n(E_(2)))/(n(S))=(8)/(24)=(1)/(3)`
