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Compute the heat generated while transferring `96000` coulombs of charge in one hour through a potential difference of `50 V`.

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Give Change, Q = 96000C
Time, `t= 1hr = 60 xx60 = 3600s`
`"Potential difference", V=50 "volts "`
Now we know that H= Vit
`" So we have to calculate I first"`
`As I= W//t`
`therefore` I= 96000/3600=80/3 A ltbtgt `H=50xx80/3xx60xx60=4.8xx10^(6)J`
Therefore, the heat generated is `4.8xx10^(6) J.`

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