Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
78 views
in Chemistry by (71.8k points)
closed by
एक धातु (X) को जल के साथ क्रिया कराने पर एक क्षारीय योगिक, (Y) जिसका आणविक सूत्र (XOH ( आणविक द्रव्यमान 40) तथा एक गैस (Z) जो आग पकड़ लेती है, देती है। (X)(Y) तथा (Z) की पहचान कीजिये तथा समीकरण भी दे ।

1 Answer

0 votes
by (72.0k points)
selected by
 
Best answer
धातु (X) सोडियम, (Y) NaOH (जिसका आणविक सूत्र 40) तथा `(Z) H_(2)` गैस है ।
`underset((X))(2Na)+2H_(2)O rarr underset((Y))(2NaOH)+underset((Z))(H_(2))uarr`

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...