Question

For the reaction 2NO₂ (g) ⇌N₂O₄ (g), when ΔS = –176.0 JK^–1 and ΔH = –57.8 kJ mol^–1 , the magnitude of ΔG at 298 K for the reaction is .......  kJ mol^{–1 .} (Nearest integer)

Answer 1

Answer is 5

ΔG = ΔH – TΔS

ΔG = 57.8 - \(\frac{298(-176)}{1000}\)

ΔG = –5.352 kJ/mole

|Nearest integer value| = 5