Question

a. Find out the mass of one mole of CaCO₃. How many moles of calcium present in 1000g CaCO₃ ? 

b. How many moles of Oxygen present in 1000g ms of CaCO₃ ?

Answer 1

a. Mass of 1 mole of CaCO₃ = 40 + 12 + 48 = 100 gram. 

No of moles of Ca in 1000 g CaCO₃ = \(\frac{1000}{100}\) = 10 mol

b. No of moles of Ca in 10 moles CaCO₃ =10 × 1 = 10 mol 

No of moles of oxygen in 10 moles of CaCO₃ = 10 × 3 = 30mol.