Question

If the temperature of 5L of a gas at atmospheric pressure is changed from 200K to 50 K, what will be the volume?

Answer 1

 According to Charles law, \(\frac{V}{T}\) = a constant

Thus, \(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\) V₁ = 5L T₁

= 200K V₂ = ? T₂ = 50 K

∴ \(\frac{5}{200}\) = \(\frac{V_2}{50}\) ; V₂ = \(\frac{5}{200}\) x 50 = 1.25 L