Question

Twice of a number added with thrice of another number gives 23. Four times the first number and 5 times the second number when added gives 41. Find out the numbers.

First number = x

Second number = y

Answer 1

Given,

First number = x, Second number = y

2x + 3y = 23

4x + 5y = 41

2(2x + 3y) = 2 × 23; 4x + 6y = 46

(4x + 6y) – (4x + 5y) = 46 – 41;

y = 5

2x + 3 × 5 = 23

2x = 23 – 15;

x = \(\frac{8}{2}\) = 4

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