Correct Answer - `NaCl, KBr` solutions are neutral, NaCN, `NaNO_(2)` and `KF` solution are basic and `NH_(4)NO_(3)` solution is acidic.
(i) NaCl: `NaCI+H_(2)Oleftrightarrowunderset("Strong base")(NaOH)+underset("Strong acid")(HCI)`
Therefore, it is a neutral solution.
(ii) KBr: `KBr+H_(2)Oleftrightarrowunderset("Strong base")(KOH)+underset("Strong acid")(HBr)`
Therefore, it is a neutral solution.
(iii) NaCN: `NaCN+H_(2)Oleftrightarrowunderset("Weak acid")(HCN)+underset("Strong base")(NaOH)`
Therefore, it is a basic solution.
(iv) `NH_(4)NO_(3)`
`NH_(4)NO_(3)+H_(2)Oleftrightarrowunderset("Weak base")(NH_(4)OH)+underset("Strong acid")(HNO_(3))`
Therefore, it is an acidic solution.
(v) `NaNO_(2)`
`NaNO_(2)+H_(2)Oleftrightarrowunderset("Strong base")( NaOH)+underset("Weak acid")(HNO_(2))`
Therefore, it is a basic solution.
(vi) KF `KF+H_(2)Oleftrightarrowunderset("Strong base")(KOH)+underset("Weak acid")(HF)`
Therefore, it is a basic solution.