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A gas cylinder containing cooking gas can withstand a pressure of 14.9 atmospheres. The pressure gauge of the cylinder indicates 12 atmosphere at `27^(@)C`. Due to sudden fire in the building, the temperature starts rising .At what temperature the cylinder will explode ?

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Correct Answer - C
`P_(1)`=12 atm, `T_(1)`=300 K, `P_(2)`=14.9 atm, `T_(2)`=?
As volume of the cylinder is constant, `(P_(1))/(T_(1))=(P_(2))/(T_(2))`

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