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In the given figure, ABCD is a trapezium whose diagonals AC and BD intersect at O such that OA = (3x – 1) cm,

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In the given figure, ABCD is a trapezium whose diagonals AC and BD intersect at O such that OA = (3x – 1) cm, OB = (2x + 1)cm, OC = (5x – 3)cm and OD = (6x – 5)cm. Then, x = ? 

(a) 2 (b) 3 (c) 2.5 (d) 4

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(a) 2 

We know that the diagonals of a trapezium are proportional.

When x = 1/2, 6x -5 = -2 < 0, which is not possible.

Therefore, x = 2

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