i. In ∆DEF, ∠DFE = 90° and FG ⊥ ED [Given]
∴ FG2 = GD × EG [Theorem of geometric mean]
∴ 122 = 8 × EG.
∴ EG = \(\frac{144}{8}\)
∴ EG = 18 units
ii. In ∆FGD, ∠FGD = 90° [Given]
∴ FD2 = FG2 + GD2 [Pythagoras theorem]
= 122 + 82 = 144 + 64
= 208
∴ FD \(=\sqrt{208}\) [Taking square root of both sides]
∴ FD \(=4\sqrt{13}\) units
iii. In ∆EGF, ∠EGF = 90° [Given]
∴ EF2 = EG2 + FG2 [Pythagoras theorem]
= 182 + 122 = 324 + 144
= 468
∴ EF \(=\sqrt{468}\) [Taking square root of both sides]
∴ EF \(=6\sqrt{13}\) units.