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Mass percentage (w/w) of ethylene glycol `(HOCH_(2)-CH_(2)OH)` in a aqueous solution is 20, then mole fraction of solute is

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Mass percentage (w/w) of ethylene glycol `(HOCH_(2)-CH_(2)OH)` in a aqueous solution is 20, then mole fraction of solute is
A. `0.5`
B. `0.067`
C. `0.1`
D. `0.4`
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Correct Answer - B
Mass of ethylene glycol `(eg) = 20g`
Mass of `H_(2)O(w) = 80g`
`n_(eg) = (20)/(62), n_(w) = (80)/(18)`
`rArr X_(eg) = (n_(eg))/(n_(eg)+n_(w))`
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