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Assuming fully decomposed, the volume of `CO_(2)` released at N.T.P on heating 9.85 g of `BaCO_(3)` (Atomic mass of Ba = 137) will be :
A. 0.84 L
B. 2.24 L
C. 4.06 L
D. 1.12 L

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Correct Answer - D
`{:(BaCO_(3),overset("Heat")(rarr),BaO+CO_(2)),(137+12+48,,22.4L),(=197g,,(22.4)/(197)xx9.85),(=9.85g,,=1.12L):}`

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