Question

Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (at. Wt. `=78.4)`, then minimum molecular weight of peroxidase anhydrase enzyme is:
A. (a)`1.568xx10^(3)`
B. (b)`15.68`
C. (c )`1.568xx10^(4)`
D. (d)`2.136xx10^(4)`

Answer 1

Correct Answer - C
Suppose the mol. Wt. of enzyme =x
Given `100 g` of enzyme wt of `Se=0.5 g`
`:.` In x g of enzyme wt. of Se` =0.5/100 xx x`
Hence `78.4=(0.5xx x)/100`
`:. X=15680=1.568xx10^(4)`