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A `1-KW` motor pumps out water from a well `10m` deep. Calculate the quantity of water pumped out per second.

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Power, `P=1kW=10^3W`, `S=10m`, time, `t=1s`,
mass of water, `m=?`
`Power=(mgxxS)/(t)`
`10^3=(mxx10xx10)/(1)` or `m=(10^3)/(10xx10)kg=10kg`

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