Question

A juggler throws ball into air. He throus one whenever the previus one is at its highest point. How high do the balls rise if he throus (n) balls each second. Acceleration the to gravity=g`.

Answer 1

Since the juggler is throwing (n) balls each second and he throws second ball when the first ball is at the highest point, so time taken by each ball to reach the highest point is ` t= 1//n`.
Taking vertical upward motion ofball up to the highest point,we have,
` v=0., a=- g, t=1/n, u=?`
As, ` v=u +at,`
so `0= u+ (-g) 1//n`
or `u= g//n` ...(i) 25 s`,
Also, ` v^(2) =u^(2) + 2 as,
so ` 0=u^(2) -2gh`,
e.l. ` h=(u^(2) //2 g) =g (2 n^(2)`.