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Determine the value of k for which k2 + 4k + 8, 2k2 + 3k + 6 and 3k2 + 4k + 4 are in A.P.

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Since,  k2 + 4k + 8, 2k2 + 3k + 6 and 3k2 + 4k + 4 are in A.P.

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