The correct option is B. 16 times
Root mean square velocity,
\(v = \sqrt\frac{2RT}{m} \Rightarrow T \propto v^2\)
\(\frac{T_2}{T_1} = \frac{V^2_2}{V_1^2} = \frac{(V_1/2)^2}{V_1} = \frac{1}{4} \) .......(i)
From TVγ−1 = constant
\(\Rightarrow \frac{V_2}{V_1} = (\frac{T_1}{T_2})^{\frac{1}{\gamma -1}}\)
\(\frac{V_2}{V_1} = (4)^{\frac{1}{1.5-1}} = 4^2 = 16\)
Hence the gas has to be expanded by 16 times.