Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
64 views
in Physics by (76.7k points)
closed by
A disc of circumference `s` is at rest at a point `A` on a horizontal surface when a constant horizontal force begins to act on its centre. Between `A` and `B` there is sufficient friction toprevent slipping, and the surface is smooth to the right of `B.AB = s`. The disc moves from `A` to `B` in time `T`. To the right of `B`,
image.
A. the angular acceleration of the disc will disappear, linear acceleration will remain unchanged
B. linear acceleration of the disc will increase
C. the disc will make one rotation in time T/2
D. the disc will cover a distance greater then s in further time T.

1 Answer

0 votes
by (76.5k points)
selected by
 
Best answer
Correct Answer - A
To the right of B the friction force will disppear so `alpha=0`, linear acc. Increases so disc cover distance greater than s in time T to the right of B the `omega` is maximum and in `T//2` one revolution will complete

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...