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A particle performing uniform circular motion gas angular momentum `L`. If its angular frequency is double and its kinetic energy halved, then the new angular momentum is :
A. 2L
B. 4L
C. L/2
D. L/4

1 Answer

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Correct Answer - D
Kinetic energy =`1/2 L omega`
`(K_(1))/(K_(2))=(L_(1)omega_(1))/(L_(2)omega_(2))`
`L_(2)=L//4`

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