Correct Answer - b
Let `T_(1)` and `T_(2)` be the tensions in two strings as shown in the figure.
For translation equilibrium along the horizontal direction, we get
`T_(1)sintheta_(1)=T_(2)sintheta_(2)`
For rotational equilibrium about G
`-T_(1)sintheta_(1)d+T_(2)costheta_(2)(L-d)=0`
`T_(1)costheta_(1)d=T_(2)costheta_(2)(L-d)`
Dividing equation (i) by (ii), we get
`(tantheta_(1))/(d) = (tantheta_(2))/(L-d)` or `(L-d)/(d) = (tantheta_(2))/(tantheta_(1))`
`(L/d-1) = (tantheta_(2))/(tantheta_(1)) rArr L/d= (tantheta_(2))/(tantheta_(1))+1`
`L/d= (tantheta_(2)+tantheta_(1))/(tantheta_(1)) rArr d=L(tantheta_(1))/(tantheta_(1)+tantheta_(2))`