Question

Position-time graph of a particle in motion is shown in fig. Calculate -

(i) Total distance covered
(ii) Displacement
(iii) Average speed
(iv) Average velocity.

Answer 1

(i) Total distance tavelled ltBrgt `" " = x_(OA) + x_(AB) + x_(BC) + x_(CD)`
`" " = 40 + 40 + 20 + 20 = 120` m

(ii) Displacement = final position - initial position
`" " = x_D- x_O =0 -0 =0`
(iii) Average speed = `("Total distance")/("Total time") = (120)/(6) = 20 m//s`
(iv) Average velocity = `("displacement")/("Time") = (0)/(6) = 0 m//s`