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A rod of mass m and length l is held vertically on a smooth horizontal floor. Now it is released from this position, find the speed of its centre of m

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A rod of mass m and length l is held vertically on a smooth horizontal floor. Now it is released from this position, find the speed of its centre of mass when it makes an angle `theta` with the vertical.
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Correct Answer - [`(sqrt(6gl)sin"(theta)/(2)costheta)/(sqrt1+3sin^(2)theta)`]
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