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in Distance, Time and Speed by (95.5k points)
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An inspector is 228 meter behind the theif . The inspector runs 42 meters and the thief runs 30 meters in a minute . In what time the inspector catch the thief ?
A. 19 minutes
B. 20 minutes
C. 18 minutes
D. 21 minutes

1 Answer

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by (94.8k points)
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Best answer
Correct Answer - A
Inspector s 228 meter behind the thief and now after some x distance he will catch the theif . So ,
`(x)/(30) = (228 + x)/(42) ` , we will get x = 570m
So time taken by inspector to catch the thief
`= ((228 + 570))/(42) = 19 `minutes
Alternate Method :
Total time to catch = `(("Distance between the two"))/(("Relative speed"))`
`(228)/((42-30)) = (228)/(12) = 19 `minutes

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