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in Trigonometry by (92.4k points)
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If `theta=3alpha` and `sin theta=(a)/(sqrt(a^(2)+b^(2))` , the value of the expression `a co sec alpha-b sec alpha` is
A. `(a)/(sqrt(a^(2)+b^(2))`
B. `2sqrt(a^(2)+b^(2))`
C. a+b
D. none of these.

1 Answer

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Best answer
Correct Answer - B
`(sqrt(a^(2)+b^(2)))/(sin alpha cos alpha)[(a)/(sqrt(a^(2)+b^(2)))cosalpha-(b)/sqrt(a^(2)+b^(2))sinalpha]``(sqrt(a^(2)+b^(2)))/(sin alpha cos alpha)[(a)/(sqrt(a^(2)+b^(2)))cosalpha-(b)/sqrt(a^(2)+b^(2))sinalpha]`` (sqrt(a^(2)+b^(2)))/(sin alpha cos alpha)[(a)/(sqrt(a^(2)+b^(2)))cosalpha-(b)/sqrt(a^(2)+b^(2))sinalpha]`
Now, `sin3 alpha=(a)/sqrt(a^(2)+b^(2))` gives
`sqrt(a^(2)+b^(2))` `[(sin3alphacos alpha-cos 3alpha sin alpha)/(sin alpha cos alpha)]=2sqrt(a^(2)+b^(2))`

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