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Three forces acting on a body are shown in the figure. To have the resultant force only along the y-direction, the magnitude of the minimum additional force needed is -
image
A. `(sqrt3)/(4)N`
B. `sqrt3N`
C. `0.5N`
D. `1.5N`

1 Answer

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Best answer
Correct Answer - C
4N nad 2N are opposite
So net `=4-2=2N`
Now figure becomes
image
Horizontal component of 2N along `-ve`
x-direction is `x_(1)=2 sin 30^(@)=1N`
Horizontal component of 1 N along `+ve`
x-direction is `x_(2)=1 cos 60^(@)=(1)/(2)N`
So, net horizontal force is `(1)/(2)N` along `-ve`
x-direction. hence `(1)/(2)` N is required in `+ve`
x-direction

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