Correct Answer - D
(a) `CuSO_(4)toCu+O_(2),CuCl_(2)toCu+Cl_(2)`
(b) `KCl toH_(2)+Cl_(2),KItoH_(2)+I_(2)`
(c) `AgNO_(3)toAg+O_(2),Cu(NO_(3))_(2)toCu+O_(2)`
(d) `KCl to H_(2)+Cl_(2),NaCl toH_(2)+Cl_(2)`
(e) `CuBrtoCu+Br_(2),CuSO_(4)toCu+O_(2)`
Thus, KCl and NaCl solutions give the same products at anode and cathode.