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A copper wire of resistance `R` is cut into ten parts of equal length. Two pieces each are joined in series and then five such combination are joined in parallel. The new combination will have resistance
A. `R`
B. `R/4`
C. `R/5`
D. `R/25`

1 Answer

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by (93.6k points)
 
Best answer
Correct Answer - D
Five parallel combination, each of value
`R/10+R/1=R/25`

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