One angle of a pentagon = 120°
Let remaining four angles be x, x, x and x
Their sum = 4x + 120°
But sum of all the interior angles of a pentagon = (2n – 4) x 90°
= (2 x 5 – 4) x 90° = 540°
= 3 x 180° = 540°
∴ 4x + 120° = 540°
4x = 540° – 120°
4x = 420
x = (420/4)° ⇒ x = 105°
∴Equal angles are 105° (Each)