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in Mathematics by (62.0k points)

If one angle of a pentagon is 120° and each of the remaining four angles is x°, find the magnitude of x.

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One angle of a pentagon = 120°

Let remaining four angles be x, x, x and x

Their sum = 4x + 120°

But sum of all the interior angles of a pentagon = (2n – 4) x 90°

= (2 x 5 – 4) x 90° = 540°

= 3 x 180° = 540°

∴ 4x + 120° = 540°

4x = 540° – 120°

4x = 420

x = (420/4)° ⇒ x = 105°

∴Equal angles are 105° (Each)

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