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An electric kettle of `1200W`has 1 kg water at `20^@C`. The water equivalent of the kettle is `500g`. The time required to heat water from `20^(@) to 100^(@)C` will be (specific heat of water = `4200 J//kg^(@)C)`.
A. 5min
B. 6 min
C. 7 min
D. 8min

1 Answer

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Correct Answer - C
`H = Pt = ms Delta theta`
`1200t = (1+0.5) (4200)(100-2)`
`t = 420 sec = 7 min`.

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